At 2009-05-29 16:48 +0100, W Charlton wrote:
Does anyone know an elegant solution to counting all elements in an XML
fragment where the elements to be counted are nested in a tree? An example
of the XML is below:
Perhaps I'm missing something, but you can just use count() and
address the nodes you want. Are you asking, perhaps, about some kind
of qualification of nodes?
The count in this case would be 8.
I hope the example below helps.
. . . . . . . Ken
T:\ftemp>type charlton.xml
<xmltree>
<countmein>Node1</countmein>
<nodes>
<node>
<countmein>Node2</countmein>
<level>1</level>
<nodes>
<node>
<countmein>Node3</countmein>
<level>2</level>
<nodes>
<node>
<countmein>Node4</countmein>
<level>3</level>
<nodes/>
</node>
</nodes>
</node>
<node>
<countmein>Node5</countmein>
<level>2</level>
<nodes/>
</node>
<node>
<countmein>Node6</countmein>
<level>2</level>
<nodes/>
</node>
</nodes>
</node>
<node>
<countmein>Node7</countmein>
<level>1</level>
<nodes>
<node>
<countmein>Node8</countmein>
<level>2</level>
<nodes/>
</node>
</nodes>
</node>
</nodes>
</xmltree>
T:\ftemp>call xslt charlton.xml charlton.xsl
8
T:\ftemp>type charlton.xsl
<?xml version="1.0" encoding="US-ASCII"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="2.0">
<xsl:output method="text"/>
<xsl:template match="/">
<xsl:value-of select="count(//countmein)"/>
</xsl:template>
</xsl:stylesheet>
T:\ftemp>
--
XSLT/XSL-FO/XQuery hands-on training - Los Angeles, USA 2009-06-08
Crane Softwrights Ltd. http://www.CraneSoftwrights.com/s/
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