Re: [xsl] how to limit number of items shown

Thanks I'll try that.
I was going to try the for-each loop looping over all items
and then inside the loop have the <xsl:if test="(position() &lt < 11)">

But I just was not sure if that is the best way to implement the limit of items.

From the point of view of XSLT, xsl:for-each loop is real :)


Yes, the for-each is real foreach loop, I mean the XSL does not have a
real 'for' loop like this:

 for(i = 0; i<=10; i++){

}

And, as I mentioned before, I need this to be done with XSL 1.0




On Sun, May 31, 2009 at 1:04 AM, Mukul Gandhi 
<gandhi(_dot_)mukul(_at_)gmail(_dot_)com> wrote:

On Sun, May 31, 2009 at 6:31 AM, Dmitri Snytkine 
<d(_dot_)snytkine(_at_)gmail(_dot_)com> wrote:

What I need is a way to make sure I show no more than 10 items, even
if XML has 25 items.


I think, you can do:

<xsl:for-each select="item[position() &lt; 11]">
 ..
</xsl:for-each>

you only iterate the items you are interested in.

I know XSL 1 does not have a real "for loop", only foreach


From the point of view of XSLT, xsl:for-each loop is real :)

btw, with XSLT 2.0 one can do (not possible in 1.0):

<xsl:for-each select="1 to 10">
  ..
</xsl:for-each>


--
Regards,
Mukul Gandhi

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