This isn't working for me. I get 0 results even when I ask for the first
one:
<xsl:key name="p" match="project_staff_role" use="@staff_id"/>
<xsl:variable name="common"
select="$staff_roles[generate-id()=generate-id(key('p',@staff_id)[0])]"/>
I tried playing around with what is going into the generate-id and key
functions, but that didn't help.
I'm not sure what's really going on in the above statement. If I don't
look at it too carefully I can intuit what's going on, but when I look
at it closely it doesn't quite make sense.
generate-id(key('p',@staff_id)[0])] is the most confusing part.
Why the @staff_id in the key but not in the generate_id()? I thought
that generate_id produced unique values for each element (in this case
staff_id) wouldn't the [0] element just give you the first staff_id?
When I think about this I wonder if the [0] goes somewhere else.
I appreciate your time.
Joelle
David Carlisle wrote:
Now I want to find all of the people in <project_staff_roles> who are
listed more than, arbitrarily, 5 times.
<xsl:key name="p" match="project_staff_role" use="@staff_id"/>
....
<xsl:for-each
select="project_staff_roles/project_staff[generate-id()=generate-id(key('p',@staff_id)[6])">
David
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