Is there a simple way for format-date() to output a localised
date format?
For example, given xs:date("2009-06-13") and a picture string
of "[D01]-[M01]-[Y0001]", is it possible to supply a country
code such as "US" and have month-day-year output? Or do you
need to define each picture string yourself, and choose the
right one based on a supplied country code?
You would need to write your own function wrapping format-date() which knows
the preferred formats for particular countries.
Many countries (for example the UK) do not really have a preferred format -
preferences are a matter of personal or corporate style.
Regards,
Michael Kay
http://www.saxonica.com/
http://twitter.com/michaelhkay
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