Thank you. It works.
I was close and yet so far...
On Sat, Jun 20, 2009 at 11:24 AM, Michael
Müller-Hillebrand<mmh(_at_)cap-studio(_dot_)de> wrote:
You got it almost:
<xsl:apply-templates select="*[not(name() = 'label')]"/>
- Michael
Am 20.06.2009 um 17:21 schrieb Dmitri Snytkine:
Hello!
I am having a little trouble doing this:
In one of my templates I have this code:
<xsl:if test="./label">
<b>
<xsl:apply-templates select="./label"/>
</b>
</xsl:if>
So, I applied the templates to a 'label' node, and then I want to
apply the templates to the rest of child nodes
but of cause I don't want to select 'label' node anymore.
I need to select all child nodes except for the 'label'
I tried this, but this does not work and generates an error in parser:
<xsl:apply-templates select="not(*[name() = 'label'])"/>
What is the correct way to select all nodes EXCEPT for one with specific
name?
Thank you.
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