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Re: [xsl] Using outer context node inside for-each

2009-07-08 17:18:02
At Wed, 08 Jul 2009 13:42:59 -0400,
G. Ken Holman wrote:

At 2009-07-08 18:31 +0100, Richard Lewis wrote:
Hi there,

Here is an abstraction of my problem template:

 <xsl:template match="record">
   <xsl:param name="show-fields" />
   <xsl:variable name="this" select="." />

   <xsl:for-each select="str:tokenize($show-fields)">
     <xsl:message><xsl:value-of select="$this/field[(_at_)name=(_dot_)]" 
/></xsl:message>

Inside the predicate "." refers to the node found by the node test.

You want [(_at_)name=current()] to address the context item that is at the 
start of the XPath expression.

Though I see Martin has taken the problem away with a more compact 
solution ... still, you wanted to know why yours wasn't working.

I hope this helps.

Excellent. Works great. Thanks very much for your help.
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Tel: +44 (0)20 7078 5134
Skype: richardjlewis
JID: ironchicken(_at_)jabber(_dot_)earth(_dot_)li
http://www.richard-lewis.me.uk/
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