Scott Trenda wrote:
Out of curiosity, wouldn't the Perl external-document approach be inaccurate
due to the way XSLT function results are (supposed to be) evaluated and
stored? That is, if you had this:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="html" encoding="UTF-8" />
<xsl:template match="/">
<html>
<body>
<div>rand(6): <xsl:value-of select="document('/cgi-bin/rand.pl?6')"
/></div>
<div>rand(6): <xsl:value-of select="document('/cgi-bin/rand.pl?6')"
/></div>
<div>rand(6): <xsl:value-of select="document('/cgi-bin/rand.pl?6')"
/></div>
<div>rand(6): <xsl:value-of select="document('/cgi-bin/rand.pl?6')"
/></div>
<div>rand(6): <xsl:value-of select="document('/cgi-bin/rand.pl?6')"
/></div>
<div>rand(6): <xsl:value-of select="document('/cgi-bin/rand.pl?6')"
/></div>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
Wouldn't that output the same result six times because (theoretically) the
XSLT processor should only have to retrieve the contents of
document('/cgi-bin/rand.pl?6') once, and just use the retrieved content for
each successive call? It is the same URI, after all, but I'm not sure just
how the gears of the big XSLT processors work in this situation.
You could get around that limitation by adding a counter or some other
unique identifier to the query string so that it looks like a different
document is being requested. On the Perl side, it will just ignore any
erroneous parameters.
~ Scott
-----Original Message-----
From: Hermann Stamm-Wilbrandt [mailto:STAMMW(_at_)de(_dot_)ibm(_dot_)com]
Sent: Wednesday, July 22, 2009 7:43 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] question on random numbers for browser XSLT
I want random numbers in a stylesheet but I am bound to XSLT 1.0 and
not able to make use of "http://exslt.org/random"; extensions because
the stylesheet should be accessed by <?xml-stylesheet ...?> in a
browser XML document.
Is there a pure XSLT solution?
(the quality of the generated random numbers is not that important)
After some playing around I found below (not pure XSLT) solution.
Important is that the PERL script lives in the same domain as the
stylesheet. You may try it out (random number "0-5") by clicking here:
http://stamm-wilbrandt.de/en/xsl-list/random/rand6.xml
$ cat rand6.xml
<?xml version="1.0" encoding="ISO-8859-1"?>
<?xml-stylesheet type="text/xsl" href="rand6.xsl"?>
<tag/>
$ cat rand6.xsl
<xsl:stylesheet
version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="html" encoding="UTF-8"/>
<xsl:template match="/">
<xsl:variable name="rand"
select="document('/cgi-bin/rand.pl?6')"/>
<html><body>rand(6): <xsl:value-of select="$rand"/></body></html>:
</xsl:template>
</xsl:stylesheet>
$
$ cat cgi-bin/rand.pl
#!/usr/bin/perl -w.
print "Content-type: text/xml\n\n";
printf("<?xml version=\"1.0\"?>\n");
printf("<rand>%d</rand>\n", rand($ARGV[0]));
printf("<!-- PERL rand(%d) -->\n",$ARGV[0]);
Mit besten Grüßen / Best wishes,
Hermann Stamm-Wilbrandt
Developer, XML Compiler
WebSphere DataPower SOA Appliances
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