[xsl] How to replace a reference to a tag by the tag itself?

As you may know XML Schema files allow the following declaration inside a XML 
Schema file:

<xsd:sequence>
<xsd:group ref="foobar"/>
</xsd:sequence>
....
<xsd:group name="foobar">
....stuff of foobar
</xsd:group>

I would like to write now a XSLT script which replaces the reference by the tag 
itself or - alternatively - by a Type declaration.

So after application of this XSLT script the resulting XML Schema file should 
look like either

<xsd:sequence>
....stuff of foobar
</xsd:sequence>

or

<xsd:sequence>
<xsd:element name="foobar" type="foobarType"/>
</xsd:sequence>
....
<xsd:ComplexType name="foobarType">
....stuff of foobar
</xsd:ComplexType>


How would such a XSLT script look like?

Thank you
Ben










--~------------------------------------------------------------------
XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--