xsl-list
[Top] [All Lists]

[xsl] How to generate an xmlns attribute with a prefix

2009-08-06 14:31:23

Hello,
I am transforming with XSL a source XML to a target XML. I can design the 
source XML myself. I can not decide on the structure of the target XML.
The target XML must have as its root element the following piece of XML:
<beans xmlns="http://www.springframework.org/schema/beans"; 
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"; 
xsi:schemaLocation="http://www.springframework.org/schema/beans 
http://www.springframework.org/schema/beans/spring-beans-2.5.xsd"; 
default-lazy-init="true">

I could obtain the xmlns attribute in my target XML, by putting it in the 
<xsl:stylesheet> element.
But I do not find a way to generate either the xmlns:xsi and xsi:schemaLocation 
attributes.
I read a lot of FAQs on namespaces and prefixes but could not find an answer.

I use:
XML version 1.0
XSLT Stylesheet version 1.0
Xalan XSLT processor Xalan-Java v 2.7.1 (but I donot use Java, I use XSL)

All help is much appreciated!
Marc


      

--~------------------------------------------------------------------
XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--

<Prev in Thread] Current Thread [Next in Thread>