Contact[contains(Name,'test1')]
Depending on where ever your context node is.
Or perhaps
/List/Contact[starts-with(Name,'test1')]
if starting from the root.
Note that an XPath expression returns a set of nodes - this expression will
return two Contact nodes. It does not return the children of the Contact
nodes directly. But the children are still there - you can navigate from the
selected nodes to their children, their ancestors, or anywhere else. So for
example if in XSLT you do
<xsl:copy-of select="/List/Contact[contains(Name,'test1')]"/>
you will get copies of the subtrees rooted at these Contact nodes.
Regards,
Michael Kay
http://www.saxonica.com/
http://twitter.com/michaelhkay
-------Original Message-------
From: Andy Kohn
Date: 8/10/2009 9:34:48 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] XPath to get node with sons with specific text
Using XPath, is it possible for me to select a whole branch
by Searching for the first child to contain some specific text.
For example for the following XML:
<List>
<Contact>
<Name>test1test</Test>
<Data>sample data</Data>
<Data>sample</Data>
<Data>sample 123</Data>
</Contact>
<Contact>
<Name>test133</Test>
<Data>sample data</Data>
</Contact>
<Contact>
<Name>test2test</Test>
<Data>sample data</Data>
<Data>sample</Data>
<Data>sample 123</Data>
</Contact>
</List>
If I search for "test1" I want from the Xpath to return the
first <Contact> and the second <Contact>, including all child
nodes (<Name> And <Data>):
<Contact>
<Name>test1test</Test>
<Data>sample data</Data>
<Data>sample</Data>
<Data>sample 123</Data>
</Contact>
<Contact>
<Name>test133</Test>
<Data>sample data</Data>
</Contact>
Something like:
//Name[contains(.,'Ab')]
But this returns only the Name node, and not all the childs.
Thanks,
Andy.
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