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Re: [xsl] Create XML from XPath expressions

2009-08-18 09:54:00
There are techniques to do it all in a single stylesheet, but it
sounds like a meta-stylesheet could be what you need - google that
term and have a look at xsl:namespace-alias:

http://www.w3.org/TR/xslt20/#element-namespace-alias

2009/8/18 Heiko Niemann <kontakt(_at_)heiko-niemann(_dot_)de>:
I would like to build the new document based on the data in the diff
result xml. As far as I know there are no dynamic templates, so there is
no way to use the xpath expression of the Path element in the match
attribute. But I might be wrong. The term meta-stylesheet sounds good -
had not heard of it yet - and I need to do some research on it.

Thanks, Heiko


Or possibly a meta-stylesheet that would create something like (as
part of an identity transform):

<xsl:template match="/item/street">
  <xsl:copy>
    <xsl:apply-templates select="@*"/>
    <xsl:text>2020 Washington Ave.</xsl:text>
  </xsl:copy>
</xsl:template>


2009/8/18 Michael Ludwig <mlu(_at_)as-guides(_dot_)com>:
Heiko Niemann schrieb:

<Difference>
<Type>update</Type>
<Path>/item/street</Path>
<NodeType>Element</NodeType>
<NodeName>street</NodeName>
<NewValue>2020 Washington Ave.</NewValue>
</Difference>

Now I want to build a new xml based on the XPath expressions in each
Path element just using XSLT.

Moin Heiko,

I think you need an eval function to achieve what you want, which seems
to be dynamically evaluating XPath expressions supplied as strings.

You might want to take a look at Saxon's saxon:evaluate() extension
function.

http://www.saxonica.com/documentation/extensions/functions.html

--
Michael Ludwig

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