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RE: [xsl] how to keep context when copying

2009-08-18 10:03:18

<xsl:function name="fdx:GetDef">
  <xsl:param name="ref"/>
  <xsl:copy-of select="key('keyItems', $ref/@OID)"/> </xsl:function>

My problem is that the nodes returned by this function lack 
ancestor info that would be useful in downstream processing 
of the node.  Is there a way that I can rewrite the function 
to return a node that allows me to get at the node's 
ancestors for example.


Just return the node itself, instead of making a copy.

<xsl:sequence select="key('keyItems', $ref/@OID)"/>

Regards,

Michael Kay
http://www.saxonica.com/
http://twitter.com/michaelhkay 


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