In XSLT 2.0 you can do
<xsl:for-each-group select="*" group-starting-with="para[(_at_)role='title']">
<paragraph>
<xsl:apply-templates select="current-group()"/>
</paragraph>
</xsl:for-each-group>
In 1.0 it's rather harder - google for "XSLT positional grouping".
Regards,
Michael Kay
http://www.saxonica.com/
http://twitter.com/michaelhkay
-----Original Message-----
From: Christian Oshiro [mailto:chris_oshiro(_at_)yahoo(_dot_)com]
Sent: 30 August 2009 17:08
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Help on XSL to tranform simple flat xml sequentially
This seems like a pretty simple thing to do, but I usually
rely on nested xml. How can I tranform xml that looks like this:
<para role=title>main title1</para>
<para role=subtitle>subtitle1</para>
<para>This is the body of the paragraph. 1</para> <list>some
stuff 1</list> <para role=title>main title2</para> <para
role=subtitle>subtitle2</para> <para>This is the body of the
paragraph. 2</para> <list>some stuff 2</list> <para
role=title>main title3</para> <para
role=subtitle>subtitle3</para> <para>This is the body of the
paragraph. 3</para> <list>some stuff 3</list>
I'd like to transform this using xlst to something like this:
<paragraph>
<title>main title1</title>
<subtitle>subtitle1</subtitle>
<body>This is the body of the paragraph. 1</body>
<list>some stuff 1</list>
</paragraph>
<paragraph>
<title>main title2</title>
<subtitle>subtitle2</subtitle>
<body>This is the body of the paragraph. 2</body>
<list>some stuff 2</list>
</paragraph>
<paragraph>
<title>main title3</title>
<subtitle>subtitle3</subtitle>
<body>This is the body of the paragraph. 3</body>
<list>some stuff 3</list>
</paragraph>
So i need to go node by node and test when role=title shows
up. Thanks for the insight.
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