This is what the rarely-used second argument of the document() function is
for. If you change the call from
document($filename)
to
document($filename, /)
then the relative URI is interpreted relative to the base URI of the source
document.
In XSLT 2.0 you can use resolve-uri() explicitly to construct the absolute
URI any way you like.
Regards,
Michael Kay
http://www.saxonica.com/
http://twitter.com/michaelhkay
-----Original Message-----
From: Dongsheng Song [mailto:dongsheng(_dot_)song(_at_)gmail(_dot_)com]
Sent: 16 September 2009 03:29
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Got xml base path in the xslt file
Hi all,
I use a xsl file to merge multiple xml files, the master xml
file like this:
<doc>
<doc id="Intro" />
<doc id="Configuration" />
<doc id="Index" />
</doc>
The xsl file like this:
<xsl:for-each select="doc/doc">
<xsl:variable name="fileName"><xsl:value-of select="@id"
/><xsl:text>.xml</xsl:text></xsl:variable>
<xsl:for-each select="document($fileName)">
<xsl:copy-of select="doc/div"/>
</xsl:for-each>
</xsl:for-each>
Because the file path is relative of the xsl file for 'document'
function, I have to put xsl and xml files together.
Can I got the base path of master xml file, so I can store
xsl and xml file separately?
Regards,
Dongsheng Song
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