Thank you Michael and Ken for pointing out that this is a grouping problem.
Very clear. I know this is the wrong list but it makes wonder then how you do
it with XQuery...
Thanks,
Morgan
--- On Fri, 10/16/09, Michael Kay <mike(_at_)saxonica(_dot_)com> wrote:
From: Michael Kay <mike(_at_)saxonica(_dot_)com>
Subject: RE: [xsl] empty element question
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Date: Friday, October 16, 2009, 8:15 PM
In XSLT 2.0, using positional grouping:
<xsl:for-each-group select="node()"
group-starting-with="lb">
<p>
<xsl:copy-of
select="current-group()[not(self::lb)]"/>
</p>
</xsl:for-each-group>
This is sufficiently general to handle more complex
instances than you show:
multiple <lb/> elements, other markup as children of
<p>, etc. It doesn't
handle the more complex problem of an <lb/> element
that's a descendant of
the <p> element rather than a child - that one comes
up on this list
occasionally, and is hard.
Regards,
Michael Kay
http://www.saxonica.com/
http://twitter.com/michaelhkay
-----Original Message-----
From: M C [mailto:mcundiff11(_at_)yahoo(_dot_)com]
Sent: 16 October 2009 21:05
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] empty element question
How do I transform this input document:
<div>
<p>string
1<lb/>string 2</p>
</div>
to this output document?
<div>
<p>string 1</p>
<p>string 2</p>
</div>
Thanks,
Morgan
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