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Re: [xsl] XSL-FO group by problem

2009-10-27 15:08:10
Martin and Ken,
So obvious, but I just did not see it.
Thanks
Mark
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From: "Martin Honnen" <Martin(_dot_)Honnen(_at_)gmx(_dot_)de>
Sent: Tuesday, October 27, 2009 11:08 AM
To: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Subject: Re: [xsl] XSL-FO group by problem

Mark Wilson wrote:

<xsl:for-each-group select="Item" group-by="concat(Prefix, CatalogNumber, Range)">
           <fo:block xsl:use-attribute-sets="base">
               <xsl:for-each select="current-group()">

<!-- What do I put here so that I only get one copy of the Catalog Number?
         (This code seems to go into an endless loop.)
-->
<xsl:apply-templates select="CatalogNumber" mode="do"/>

I think you want to move the above xsl:apply-templates outside of the xsl:for-each to ensure it is only done once for each group but not for each Item in each group.

                  <xsl:apply-templates select="Title" mode="do"/>

               </xsl:for-each>
           </fo:block>
       </xsl:for-each-group>



--

Martin Honnen
http://msmvps.com/blogs/martin_honnen/

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