[xsl] Obtaining a specific context position()

Hi All,
I have a nested grouping arrangement, simplified (I hope not too much or 
incorrectly) below in Listing 2.
It operates on the xml file simplified in Listing 3.

<xsl:value-of select="//List/Item/position()"/>"

returns the position of every <Item> in the list.  What I want as a result 
is the position in the <List> of the <SubDiv1>'s parent <Item>.
The output I want is in Listing 1a, the output I get is in Listing 1b.
Thanks,
Mark

Listing 1a: desired.
<List>
<Item>
   <Heading>1</Heading>
   <SubDiv1>1</SubDiv1>
</Item>
<Item>
   <Heading>2</Heading>
   <SubDiv1>2</SubDiv>
</Item>
</List>

Listing 1a: actual

<List>
<Item>
   <Heading>1</Heading>
   <SubDiv1>1 2</SubDiv1>
</Item>
<Item>
   <Heading>2</Heading>
   <SubDiv1>1 2</SubDiv>
</Item>
</List>


Listing 2: simplified xsl:

<xsl:template match="List">
   <List>
       <xsl:for-each-group select="Item" group-by="Heading" 
collation="{$sorting-collation}">
       <xsl:sort select="current-grouping-key()" 
collation="{$sorting-collation}"/>
           <Item>
              <Heading>
                 <xsl:value-of select="position()"/> <!-- first call -->
               </Heading>

               <xsl:for-each-group select="current-group()" 
group-by="SubDiv1">
               <xsl:sort select="current-grouping-key()" 
collation="{$sorting-collation}"/>
                   <SubDiv1>
                        <xsl:value-of select="//List/Item/position()"/> 
<!-- second call -->
                   </SubDiv1>
           ...........
</xsl:template>

Listing 3: xml
<List>
   <Item>
     <Heading>Poland</Heading>
       <SubDiv1>1958</SubDiv1>
   </Item>
   <Item>
     <Heading >Spain</Heading>
      <SubDiv1>1958</SubDiv1>
  </Item>
</List> 


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