At 2009-12-04 17:04 -0500, Philip Vallone wrote:
This is a pure xpath question.
Which is frequently asked.
Suppose I have a namespace declaration like this:
<organizations version="1.0" xmlns="http://www.imsglobal.org/xsd/imscp_v1p1">
The namespace does not have a prefix.
Right, but the element node in the tree has the namespace in the expanded name.
I want to use local-name() to access the nodes
Why? That would be improper. You want to use qualified names
representing expanded names to access the node.
but not sure how. For example, how do I access a path like this:
XPATH:
/organizations/organization/title[2]/title
In an XSLT 1 or XSLT 2 stylesheet:
xmlns:ims="http://www.imsglobal.org/xsd/imscp_v1p1"
...
/ims:organizations/ims:organization/ims:title[2]/ims:title
XML:
<organizations version="1.0"
xmlns="http://www.imsglobal.org/xsd/imscp_v1p1">
<organization>
<title>SCORM 2004 4th Edition Manifest
Basics Content Example 1.0</title>
...
The expanded name in the stylesheet must match the expanded name in
the XML data. The qualified name in the stylesheet can be different
than the qualified name in the XML data. The qualified name in the
stylesheet cannot use the default namespace in XSLT 1.
In XSLT 2 you can use xpath-default-namespace= to support unprefixed
names in XPath, but I've come to the conclusion it isn't helpful when
more than one input namespace is in use.
I hope this helps.
. . . . . . . . . . . Ken
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