Thx Michael,
Using the schema aware processor would probably only make sense if I
were to apply a single xslt on an xml document referencing a schema.
However, I'm using cocoon pipelines to process 1 document where the
intermediate results no longer conform to the original schema so these
kinds of mistakes seem unavoidable. Unless you have a good proposal for
this particular way of working?
Many thx for spotting this stupid error ;-)
Robby
-----Original Message-----
From: Michael Kay [mailto:mike(_at_)saxonica(_dot_)com]
Sent: Thursday, December 10, 2009 12:51 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] problem with boolean AND expression [false AND false
->true] in xslt2.0
Check your spelling of "entry" vs "Entry". XML is case-sensitive.
To avoid such errors, consider using schema-awareness, which will check
the
names appearing in path expressions against the names that are valid
according to the schema.
Regards,
Michael Kay
http://www.saxonica.com/
http://twitter.com/michaelhkay
-----Original Message-----
From: Robby Pelssers [mailto:robby(_dot_)pelssers(_at_)ciber(_dot_)com]
Sent: 10 December 2009 11:32
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] problem with boolean AND expression [false AND
false ->true] in xslt2.0
Hi all,
I have the weirdest problem with the result of a AND
expression of 2 booleans. I'm using Saxon8.7 FYI.
<xsl:variable name="symbolAndParameterAreEqual"
select="deep-equal($previousRow/Entry[1],
$currentRow/Entry[1]) and deep-equal($previousRow/Entry[2],
$currentRow/Entry[2])"
as="xs:boolean"/>
<xsl:comment>
symbol matches precedingrow = <xsl:value-of
select="deep-equal($previousRow/entry[1], $currentRow/entry[1])"/>
parameter matches precedingrow = <xsl:value-of
select="deep-equal($previousRow/entry[2], $currentRow/entry[2])"/>
both are equal = <xsl:value-of
select="$symbolAndParameterAreEqual"/>
</xsl:comment>
Results in
<!--
symbol matches precedingrow = false
parameter matches precedingrow = false
both are equal = true
-->
The deep-equal function always returns the good result but when
combining the two Boolean results in an AND expression they always
return True.
Anyone who can shed any light onto this problem?
Kind regards,
Robby Pelssers
http://robbypelssers.blogspot.com/
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