Mm... damn.... I thought I needed to specify the data-type ;-(
So I just came up with following solution:
<xsl:template match="table">
<table>
<xsl:variable name="numericRows" select="tr[string(number(td)) !='NaN']"/>
<xsl:variable name="alphabeticRows"
select="tr[string(number(td))='NaN']"/>
<xsl:apply-templates select="$numericRows">
<xsl:sort select="td" data-type="number"/>
</xsl:apply-templates>
<xsl:apply-templates select="$alphabeticRows">
<xsl:sort select="td" data-type="text"/>
</xsl:apply-templates>
</table>
</xsl:template>
But I also tested without specifying any data-type and you're right ...aaargh..
<xsl:template match="table">
<table>
<xsl:apply-templates select="tr">
<xsl:sort select="td"/>
</xsl:apply-templates>
</table>
</xsl:template>
Thx,
You made life a lot easier ;-)
Robby
-----Original Message-----
From: Andrew Welch [mailto:andrew(_dot_)j(_dot_)welch(_at_)gmail(_dot_)com]
Sent: Thursday, December 17, 2009 4:28 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] sorting a table based on first column which contains both
numbers and words
2009/12/17 Robby Pelssers <robby(_dot_)pelssers(_at_)ciber(_dot_)com>:
Hi all,
I have the use case where I need to sort a table based on it's first column.
This column can contain only numbers but also a mix of words and numbers. See
example below.
<table>
<tr>
<td>5</td>
</tr>
<tr>
<td>3</td>
</tr>
<tr>
<td>Banana</td>
</tr>
<tr>
<td>Apple</td>
</tr>
</table>
I want following output (first sorted numerical and then alphabetically)
<table>
<tr>
<td>3</td>
</tr>
<tr>
<td>5</td>
</tr>
<tr>
<td>Apple</td>
</tr>
<tr>
<td>Banana</td>
</tr>
</table>
How can I accomplish this with xslt?
The default sort will do that, read about xsl:sort
--
Andrew Welch
http://andrewjwelch.com
Kernow: http://kernowforsaxon.sf.net/
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