Re: [xsl] Re parsing element data generated by XSLT within the same sty

At 2009-12-29 13:31 -0500, David A. Lee wrote:
> I'm trying to learn XSLT (better).
Keep in mind there are instructor-led XSLT/XQuery training classes 
coming up in Europe and California (I've mentioned them on my home 
page and will announce them in the new year):
  http://www.CraneSoftwrights.com/s/

> I'm working with an existing complicated stylesheet that I need to 
> make changes to.
> I have a working solution where I output the XSLT piped to XQuery 
> (which I know better) but I'd like to do the whole thing in XSLT.
> The basic concept/solution I'm looking for is:  is it possible, and 
> how, to re-process generated elements that are not in the source document.
Yes, by putting those elements into a variable and then acting on the 
variable contents.
> Simplified example: suppose I have a template like this.  Suppose I 
> have LOTS of templates like these.
> <xsl:template match="v3:renderMultiMedia/v3:caption">
>        <p>
>            <xsl:call-template name="styleCodeAttr">
>                <xsl:with-param name="styleCode" select="@styleCode"/>
>                <xsl:with-param name="additionalStyleCode"
>                select="'MultiMediaCaption'"/>
>            </xsl:call-template>
>            <xsl:apply-templates select="@*[not(local-name(.)='styleCode')]"/>
>            <xsl:apply-templates mode="mixed" select="node()"/>
>        </p>
> </xsl:template>
>
> What I'd like to do is change every <p>XXX</p> into XXX&#10;
  <xsl:variable name="intermediate" as="element(p)*">
    <xsl:apply-templates/><!--this is what you are doing now-->
  </xsl:variable>
  <xsl:for-each select="$intermediate">
    <xsl:copy-of select="node()"/>
    <xsl:text>
</xsl:text>
  </xsl:for-each>

or.....

  <xsl:variable name="intermediate" as="element(p)*">
    <xsl:apply-templates/><!--this is what you are doing now-->
  </xsl:variable>
  <xsl:apply-templates select="$intermediate" mode="change-p-to-nl"/>
...
<xsl:template mode="change-p-to-nl" match="p">
  <xsl:copy-of select="node()"/>
  <xsl:text>
</xsl:text>
</xsl:template>

Of course you'll have to take away the as= constraint if in fact you 
don't always have <p> elements.
> Obviously I can edit every template to change how it generates the
> output XML, but I'm wondering is there a way to do this in XSLT by saying
> "Re-parse the generated XML by this template".
By acting on the generated XML that was placed in a variable rather 
than in the result tree.
I hope this helps.

. . . . . . . . . . . . Ken

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