Is there anyway to pass a parameter to the xslt so you don't have to
read as much of the XML document?
-----Original Message-----
From: a kusa [mailto:akusa8(_at_)gmail(_dot_)com]
Sent: Monday, January 04, 2010 11:53 AM
To: xsl-list
Subject: [xsl] reading a large XML file using document()
Hi
I have to read a large XML file and extract out information from it in
my XSLT.
I am using document() function to pass the .xml file name to the XSLT.
But this XML file has 36000 lines of data that I have to read. Can the
experts suggest a better approach to this issue?
Thanks in advance.
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