Hi Martin:
Thank you for your input.The issue I am having here is when I use
level2/item[last()], the processor considers both item elements under
<level2> as last ones. So I still get repeated <spec> elements under
both item elements.
How do I get the position of <item> relative to its preceding and
following <item> siblings?
On 1/25/10, Martin Honnen <Martin(_dot_)Honnen(_at_)gmx(_dot_)de> wrote:
a kusa wrote:
Source XML:
<root>
<level1>
<st1>
<desc><text>sample desc</text></desc>
<!-- A <spec> element can occur here as well-->
<level2>
<item><text>r1 </text></item>
<item><text>r2</text></item>
</level2>
<spec><para>Some spec 1</para></spec>
<spec><para>Some spec 2</para></spec>
</st1>
</level1>
</root>
Here is my desired output XML:
<root>
<step1>
<text>sample desc</text>
<step2>
<text>r1</text>
</step2>
<step2>
<text>r2</text>
<spec><para>Some spec 1</para></spec>
<spec><para>Some spec 2</para></spec>
</step2>
</step1>
</root>
Please note that every item under level2 becomes a step2 in my output XML.
The following stylesheet creates the output you describe from the input you
posted:
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0">
<xsl:output indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="st1/desc | st1/level2">
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="level1">
<step1>
<xsl:apply-templates select="st1/*"/>
</step1>
</xsl:template>
<xsl:template match="level2/item">
<step2>
<xsl:apply-templates/>
</step2>
</xsl:template>
<xsl:template match="level2/item[last()]" priority="3">
<step2>
<xsl:apply-templates/>
<xsl:copy-of select="../following-sibling::spec"/>
</step2>
</xsl:template>
<xsl:template match="st1/spec"/>
</xsl:stylesheet>
--
Martin Honnen
http://msmvps.com/blogs/martin_honnen/
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