Hi,
Sorry if i confused you.
Let me explain more clearly
My xml consists of 11 records ,
================================
123 ABC GOOD 10
123 ABC GOOD 20
123 ABC GOOD 30
456 DEF GOOD 10
789 GHI GOOD 10
567 JKL GOOD 10
234 BCD GOOD 20
345 CDE GOOD 20
678 TTT TRIANGULATION 30
678 TTT TRIANGULATION 20
321 TRT TRIANGULATION 20
================================
when i used group-by="concat(VAT_TAX_NO,BILL_CUST_NAME,INTRA_EU_TRX_CODE)">
These 11 records are grouping into "8" records.
and i want to capture this value and show it in o/p
these are the ways i tried..
<xsl:value-of select="count(current-group())"/> giving o/p as
<mezo eazon="0A0001D003A">31111121</mezo>
<xsl:value-of select="last()"/> giving o/p as
<mezo eazon="0A0001D003A">1111111111111111</mezo>
<xsl:value-of select="position()"/> giving o/p as
<mezo eazon="0A0001D003A">12345678</mezo>
expected o/p
<mezo eazon="0A0001D003A">8</mezo>
Thanks
Anil
On Mon, Mar 8, 2010 at 6:46 PM, David Carlisle
<davidc(_at_)nag(_dot_)co(_dot_)uk> wrote:
On 08/03/2010 13:04, anil kumar wrote:
How to show the toatal number of records,
ima failing to get this by last()
because iam grouping 11 records into 8 , so the value of last() is
giving 11 which is in correct
I didn't understand that comment, but inside xsl:for-each-group
<xsl:value-of select="last()"/> gives you the number of groups
<xsl:value-of select="count(current-group())"/> gives the number of items in
the current group.
I'm not sure which of these numbers you want.
David
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