On Thu, 8 Apr 2010 11:08:45 +0100
Andrew Welch <andrew(_dot_)j(_dot_)welch(_at_)gmail(_dot_)com> wrote:
Still leaves one side with a string...
Sure, but that's "the right way" to represent that in XML, then you
can just pass in your delimited parameter and do:
select="skillarea[targets/target = $targets]"
where $targets is a top level variable created when you tokenize the
param into a sequence of items.
Sneaky Andrew!
tokenized param as="item()*"= element value.
Yes, that works.
Thanks.
I've now got Davids idea working.
<xsl:apply-templates
select="skillarea[tokenize(@targets,'\|')=tokenize($targets,'\|')]"/>
since it's a regex, | needs escaping.
More than one way to skin a cat?
Thanks.
--
regards
--
Dave Pawson
XSLT XSL-FO FAQ.
http://www.dpawson.co.uk
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--