I find it hard to believe that this stylesheet delivered anything other than
an error: the regular expression needs to be in quotes (as a string literal)
and it's also missing an opening square bracket. If you want the 4 to be at
the start, you should also anchor it to the start: matches(., '^4[0-9]{6}')
Regards,
Michael Kay
http://www.saxonica.com/
http://twitter.com/michaelhkay
-----Original Message-----
From: Jack Bush [mailto:netbeansfan(_at_)yahoo(_dot_)com(_dot_)au]
Sent: 01 May 2010 14:56
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Could not use matches in Regular Expression (XSLT 2.0)
Hi Forum members,
I
am new to XSLT 2.0 and would like to do the following basic
numeric string pattern matching using regular expression:
<xsl:template match="ns:p[ns:strong='Telephones:']">
<xsl:choose>
< -- If global parameter $TELEPHONE_AREA_CODE equals to
FAIRYLAND -->
<xsl:when test="$TELEPHONE_AREA_CODE = ''FAIRYLAND">
<xsl:for-each select="ns:a">
<-- Only accept the phone number that starts with 4
follow by six digits.... --->
<xsl:if test="matches(.,4[0-9][0-9][0-9]0-9][0-9][0-9])">
<phone_number><xsl:value-of select='.'/></phone_number>
</xsl:if>
</xsl:for-each>/>
......
However, it is picking up phone numbers starting with 1
instead. Also tried the starts-with() with the same outcomes.
I am using JDK1.6.19, Netbeans 6.7, JDOM 1.1, Saxon 9.1 on Windows XP.
Your assistance would be much appreciated.
Thanks in advance,
Jack
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