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RE: [xsl] Could not use matches in Regular Expression (XSLT 2.0)

2010-05-01 09:12:36

I find it hard to believe that this stylesheet delivered anything other than
an error: the regular expression needs to be in quotes (as a string literal)
and it's also missing an opening square bracket. If you want the 4 to be at
the start, you should also anchor it to the start: matches(., '^4[0-9]{6}')

Regards,

Michael Kay
http://www.saxonica.com/
http://twitter.com/michaelhkay 


-----Original Message-----
From: Jack Bush [mailto:netbeansfan(_at_)yahoo(_dot_)com(_dot_)au] 
Sent: 01 May 2010 14:56
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Could not use matches in Regular Expression (XSLT 2.0)

Hi Forum members,

I
am new to XSLT 2.0 and would like to do the following basic 
numeric string pattern matching using regular expression:

<xsl:template match="ns:p[ns:strong='Telephones:']">
  <xsl:choose>
    < -- If global parameter $TELEPHONE_AREA_CODE equals to 
FAIRYLAND -->
    <xsl:when test="$TELEPHONE_AREA_CODE = ''FAIRYLAND">
      <xsl:for-each select="ns:a">
      <-- Only accept the phone number that starts with 4 
follow by six digits....   ---> 
        <xsl:if test="matches(.,4[0-9][0-9][0-9]0-9][0-9][0-9])">
          <phone_number><xsl:value-of select='.'/></phone_number>
        </xsl:if>
      </xsl:for-each>/>
  ......

However, it is picking up phone numbers starting with 1 
instead. Also tried the starts-with() with the same outcomes.

I am using JDK1.6.19, Netbeans 6.7, JDOM 1.1, Saxon 9.1 on Windows XP.

Your assistance would be much appreciated.

Thanks in advance,

Jack



      


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