Wrong approach: XSLT stylesheets produce a tree as the output, not lexical
XML; XSLT instructions create nodes on the tree, not tags in the serialized
XML. So you can't write end tags and start tags as separate operations.
This is a grouping problem and in XSLT 2.0 you can write
<xsl:for-each-group select="node" group-by="subnode">
<xsl:sort select="current-grouping-key()"/>
<table>
<xsl:for-each-select="current-group()">
....
</
</
</
It's more tricky to achieve if you're stuck with XSLT 1.0: search for
"Muenchian Grouping". The code is rather confusing, but not difficult once
you understand it.
Regards,
Michael Kay
http://www.saxonica.com/
http://twitter.com/michaelhkay
-----Original Message-----
From: Charles-Louis De Maere
[mailto:charles-louis(_dot_)demaere(_at_)ehealth(_dot_)fgov(_dot_)be]
Sent: 10 May 2010 09:14
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Trouble creating tables while looping through elements
Dear all,
I'm looping through a (sorted) list of nodes, and would like
to put them in different tables based on a certain condition
using xslt.
At the moment, I'm doing the following :
<table>
<xsl:for-each select="node">
<tbody>
... some formatting ...
</tbody>
<xsl:if test="not(subnode = following-sibling::node/subnode)">
</table>
<h2>Some Title</h2>
<table>
</xsl-if>
</xsl:for-each>
</table>
However, this XSLT file is invalid (XMLSpy indicates a
warning when I save it, because of the closing <table> tag
underneath the if-test), and Firefox refuses to display it
for the same reason.
Is there any easy way to have some kind of separation within
the for-each loop, or should I take this formatting out of the loop ?
Thanks in advance,
Charles-Louis de Maere
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