xsl-list
[Top] [All Lists]

[xsl] Moving or removing a period

2010-05-18 14:07:29
I need some help moving a period from one context to another. I can identify 
where period needs to be inserted but I can't get rid of the existing period.

Here's what a I have so far

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; 
      xmlns:xs="http://www.w3.org/2001/XMLSchema";
      exclude-result-prefixes="xs"
      version="2.0">
        <xsl:include href="copy.xsl"/>
        
        <xsl:template match="prompt">
                <xsl:if test="parent::link/following-sibling::text() ='.'">
                        <prompt>
                                <xsl:value-of select="."/><xsl:text>.</xsl:text>
                        </prompt>
                </xsl:if>
        </xsl:template>

A snippet of the pertinent XML looks something like this: (there's a whole lot 
more to this document, hence the "copy.xsl" include).

<para>
<link linkaction="prompt" linktype="goto" xlink:href="IETM://M00206" 
xmlns:xlink="http://www.w3.org/1999/xlink"; xreftype="wp">
<prompt>This is the content stuff</prompt>
</link>.
</para>

I can get the period into the <prompt> element but I can't seem to find a good 
way to eliminate the period after the <link> end tag. I cannot perform a simple 
search and replace because there are cases when a <link> element does NOT have 
a child <prompt> element, so that period needs to remain. I only want to 
eliminate "." when <link> contains a child <prompt>.

The parent of <link> is usually either <para> or <trim.para>.



C Flanders


--~------------------------------------------------------------------
XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--

<Prev in Thread] Current Thread [Next in Thread>