I'm sorry that you are having trouble understand the responses you were
given. I'm afraid I may just be repeating the same response in slightly
different words.
I am writing this function:
---------------
<xsl:function name="fnc:getPatientRolePath">
<xsl:param name="Version"/>
<xsl:choose>
<xsl:when test="$Version = '3.0'">
<xsl:
select="/n1:Document/n1:recordTarget/n1:patientRole"/>
</xsl:when>
<xsl:otherwise>UNDEFINED</xsl:otherwise>
</xsl:choose>
</xsl:function>
As I explained in my previous response, "xsl:" is not a valid XML element
name, so this won't even get past the XML parser.
---------------
I am writing this function so as to create a variable
patientRolePath to hold the value:
/n1:Document/n1:recordTarget/n1:patientRole.
As David Carlisle explained in his response, you can't hold fragments of
XPath expressions in variables, you can only hold values. However, that's
fine: to do what you describe below, you don't need to hold the path in the
variable, you can hold the set of nodes selected by the path.
This is because then I can use the variable name
patientRolePath and append child nodes and get required
values such as:
$patientRolePath/id
$patientRolePath/lastName
$patientRolePath/firstName
However this that function I can't seem to write it to return
with the path.
<xsl: select="/n1:Document/n1:recordTarget/n1:patientRole"/>
is not valid
Correct, "xsl:" is not a valid element name.
As I explained before, it's useful to tell us what error messages you are
getting, rather than simply saying something doesn't work. Then we can
explain the error to you.
HOWEVER <xsl:variable name="patientRole"
select="/n1:Document/n1:recordTarget/n1:patientRole"/>
written as a statement is valid. But does not return me anything.
A variable declaration on its own doesn't return anything. A reference to
the variable would return something, but a variable that is never referenced
is useless.
Regards,
Michael Kay
http://www.saxonica.com/
http://twitter.com/michaelhkay
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