Lucas Miguez wrote:
I have a problem with the namespace of an XML file. The header of that
file is that:
<?xml version="1.0" encoding="windows-1252"?>
<AuditFile xmlns="urn:OECD:StandardAuditFile-Tax:PT_1.00_01">
<xsl:stylesheet version="1.0" xmlns:xsl="
http://www.w3.org/1999/XSL/Transform";
xmlns="urn:OECD:StandardAuditFile-Tax:PT_1.00_01" xmlns:fo="
http://www.w3.org/1999/XSL/Format";>
....
Well, the XSL file is not showing the values of the XML file. But if I
eliminate the namespace in the XML file
(xmlns="urn:OECD:StandardAuditFile-Tax:PT_1.00_01") it works.
What is the correct way to declare that namespace in the XSL file?
With XSLT and XPath 1.0, to select and match elements in a namespace you
need to bind a prefix to the namespace URI and use that prefix in your
XPath expressions and match patterns to qualify element names
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:df="urn:OECD:StandardAuditFile-Tax:PT_1.00_01"
exclude-result-prefixes="df"
version="1.0">
<!-- now use prefix "df" to qualify element names -->
<xsl:template match="/df:AuditFile">
<html>
<body>
<xsl:value-of select="df:Header/df:CompanyID"/>
</body>
</html>
</xsl:template>
--
Martin Honnen
http://msmvps.com/blogs/martin_honnen/
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