xsl-list
[Top] [All Lists]

Re: [xsl] Could not select the text() of both parent & child nodes simultaneously

2010-06-16 09:20:17
Hi David & Michael,

I am very new to XML development, not to mention about XSLT and hesitates to 
move to version 2.0 for 3 reasons:

( i ) 1.0 is sufficient for what I need to do but there is bound to be better 
ways to do it in 2.0.

<Saxon 9 never executes XSLT 1, It only executes XSLT 2. If you give it an XSLt 
1 stylesheet it tries to emulate XSLT 1, but that is not the same thing. 
<Furthermore the stylesheet you posted was inconsistent as it claimed at the 
top to be XSLT 1 but it used XSLT2 constructs which would generate an error <if 
used with an XSLT 1 processor.

Looks like I am using XSLT 2 processor without realizing but not making use of 
its new functionalities yet.

( ii ) XPath& XSLT 2.0 comes at a cost for recent release of Saxon licensing 
models.

<No it does not. The system you are using is free, open source, and implements 
XSLT 2. The last version of saxon to implement xslt 1 was saxon 6.5.
 
My understanding on recent installation manual was the open source version 
(saxonhe9-2-0-5j.zip - Saxon9 Home Edition?
) does not support XPath/XSLT features. This download does not have Path/XSLT 
jars such as saxon9-xpath.jar, saxon9-jdom.jar supplied in Saxon 9.1. 
Otherwise, please provide the correct link to download Saxon9 Home Edition.

 ( iii ) Believes that a schema/DTD is required by the stylesheet. Not 
familiar with how to set it up yet.

<I'm not sure what you mean by this, but probably it is a misunderstanding.

How to turn off type checking in XSLT 2.0 by updating <xsl:stylesheet 
version="2.0" (line 2) to prevent the following exception from occurring:
 
  Error on line 83
  XPTY0004: Cannot compare java-type:definition.Sport to xs:string

The type checking did not take place when <xsl:stylesheet version="1.0".
 
This is a Java Application and would like to keep as much core definition in 
Java and only use XSLT for transformation purposes.


Back to the original question, what is the XPath statement in XSLT to get the 
content of both<a> (team) and<p> (goals) at the sametime?


<As I said in my first reply, the source that you posted is clearly not the 
source you used (as it is not XML) so I can not guess what code you need to 
<process your original source. The source you posted <would generate a fatal 
XML parse error before the XSLT engine started.
<If you post a well formed XML source and say what you want it to be converted 
to, then I'm sure someone will tell you the code you need.

Here goes the actual code as best as I could put it:

<html xmlns="http://www.w3.org/1999/xhtml" ; 
xmlns:html="http://www.w3.org/1999/xhtml"; >
<head>
  ……
</head>
<body onload="loadMapLocation(-46.1240, 149.543, 49, 1); setClockTime(2008, 01, 
19, 12, 36, 01); setInterval('updateTime()', 2000);"  onunload="GUnload();" >
<a shape="rect"  name="top" />
<div id="container" >
<div id="header" >
<div id="postmark" />
<a shape="rect"  class="imglink"  href="http://www.abc.com/"; >
<img id="logoimg"  src="http://www.abc.com/images/world-cup.gif" ; width="192"  
height="33"  alt="World Cup Logo" />
</a>
<hr/>
</div>
<h1>World Cup Competition</h1>
<p>
</p>
<p>
<strong>World Cup Team:</strong>
<br clear="none" />
<a shape="rect"  href="http://www.abc.com/team/brasil.html?aid=427231"; 
Brasil</a> (30 goals)
<br clear="none" />
<a shape="rect"  href=" www.abc.com/team/argentina.html?aid=427231" 
Argentina</a>(25 goals)
<br clear="none" />
<a shape="rect"  href=" www.abc.com/team/Germany.html?aid=427231" 
Germany</a>(22 goals)
<br clear="none" />
<a shape="rect"  href=" www.abc.com/team/usa.html?aid=427231" >United States of 
America</a>(15 goals)
<br clear="none" />
……
</p>
<p>
</p>
</div>
</body>
 <?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:ns="http://www.w3.org/1999/xhtml";
exclude-result-prefixes="ns">
 
<xsl:template match="/">
<group>
……..
<xsl:template match="ns:p[ns:strong='World Cup Team:']"> 
  <xsl:for-each select="text()[normalize-space() != '']">
    <team><xsl:value-of select="concat(../ns:a/normalize-space(), 
normalize-space())"/></team>
  </xsl:for-each> 
</xsl:template> 
………
</group>
 
<xsl:template match="ns:p"/>
 
</xsl:stylesheet>
 
</html>
 
Thanks,
 
Jack

----- Original Message ----
From: David Carlisle <davidc(_at_)nag(_dot_)co(_dot_)uk>
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Cc: Jack Bush <netbeansfan(_at_)yahoo(_dot_)com(_dot_)au>
Sent: Wed, 16 June, 2010 6:47:03 PM
Subject: Re: [xsl] Could not select the text() of both parent & child nodes 
simultaneously

On 16/06/2010 09:30, Jack Bush wrote:
Hi David,

I am very new to XML development, not to mention about XSLT and hesitates to 
move to version 2.0 for 3 reasons:

( i ) 1.0 is sufficient for what I need to do but there is bound to be better 
ways to do it in 2.0.

Saxon 9 never executes XSLT 1, It only executes XSLT 2. If you give it an XSLt 
1 stylesheet it tries to emulate XSLT 1, but that is not the same thing. 
Furthermore the stylesheet you posted was inconsistent as it claimed at the top 
to be XSLT 1 but it used XSLT2 constructs which would generate an error if used 
with an XSLT 1 processor.


( ii ) XPath&  XSLT 2.0 comes at a cost for recent release of Saxon licensing 
models.

No it does not. The system you are using is free, open source, and implements 
XSLT 2. The last version of saxon to implement xslt 1 was saxon 6.5.

( iii ) Believes that a schema/DTD is required by the stylesheet. Not 
familiar with how to set it up yet.
I'm not sure what you mean by this, but probably it is a misunderstanding.


Back to the original question, what is the XPath statement in XSLT to get the 
content of both<a>  (team) and<p>  (goals) at the sametime?


As I said in my first reply, the source that you posted is clearly not the 
source you used (as it is not XML) so I can not guess what code you need to 
process your original source. The source you posted would generate a fatal XML 
parse error before the XSLT engine started.
If you post a well formed XML source and say what you want it to be converted 
to, then I'm sure someone will tell you the code you need.

David

________________________________________________________________________
The Numerical Algorithms Group Ltd is a company registered in England
and Wales with company number 1249803. The registered office is:
Wilkinson House, Jordan Hill Road, Oxford OX2 8DR, United Kingdom.

This e-mail has been scanned for all viruses by Star. The service is
powered by MessageLabs. 
________________________________________________________________________

--~------------------------------------------------------------------
XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--


      


--~------------------------------------------------------------------
XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--