After you use the standard XPath 2.0 collection() function, the rest
is simple grouping.
Create the resulting files using <xsl:result-document> -- best with
the same name but in a new directory.
--
Cheers,
Dimitre Novatchev
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Truly great madness cannot be achieved without significant intelligence.
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To invent, you need a good imagination and a pile of junk
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Never fight an inanimate object
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You've achieved success in your field when you don't know whether what
you're doing is work or play
On Mon, Jun 21, 2010 at 10:31 AM, a kusa <akusa8(_at_)gmail(_dot_)com> wrote:
Hello
I have a requirement which I am not sure if this can be done in XSLT.
I will try to explain it theoretically as much as possible and please
let me know if there is any way this can be done in XSLT.
I have a bunch of XML files in a folder.
The XML files have an element called 'prod-num' which is an 8-digit
number the first 5 of which follows a particular numbering scheme
based on what the XML is for.
For example, if the XML represents books for children, the prod-num
has the following numbering scheme : 1212 - 1.
If the XML data represents books for Science, the prod-num has the
following numbering scheme: 1212-2
Now, here is what needs to happen.
The last three of the prod-num needs to be sequentially numbered if
the first 5 are the same.
So, in my explained example above, the transformation needs to read
the folder with the XML files, and read through the prod-num values.
If there are say two XML files with 1212-1, then the first one needs
to be updated with 1212-1001, the second one becomes 1212-1002.
Can the experts please give me some tips and ideas to resolve this?
Thanks in advance
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