Agreed. It seems like it would be real handy to have position() take
an argument:
position(../s[])
and return the position of the matching items...
did my count preceding-sibling suggestion not fit?
or have a different
function where you could get the position in a for expression:
for $i in ../s
if (...) then $i/position() else ()
In xquery you do
for $i at $pos in ../s return
if (...) then $pos else ()
However thats exactly the same as:
for $i in ../s return
if (...) then 1 + count($i/preceding-sibling::s) else ()
--
Andrew Welch
http://andrewjwelch.com
Kernow: http://kernowforsaxon.sf.net/
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