Re: [xsl] Recognizing new line character in XSL

Assuming that you apply-templates to text nodes, and that you are 
generating HTML, and that you are using XSLT 2.0, you can do
<xsl:apply-template match="text()">
<xsl:for-each select="tokenize(., '\n')">
<p><xsl:value-of select="."/></p>
</
</

Oh, I see you're using XSLT 1.0. That's tedious - in that case you need 
a recursive named template that uses substring-before to process the 
text before the first newline, and then calls itself passing 
substring-after(., '& #xa;') to process the text after the first newline.
Michael Kay
Saxonica

On 20/07/2010 12:13, Siddhi Thakkar wrote:
> Hi Experts,
> Could you please guide me if there is any way in XSL to recognize new line 
> character and display each line as a new paragraph? I am not sure of the Unicode 
> entity of new line char, if we really need it we can assume it to be&#xa;
> I am using JDOM as processor and xsl version 1.0.
>
> Thanks much in advance for help.
> Siddhi
>
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