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[xsl] [XPath 1.0] Why is .[A] illegal but self::node()[A] is legal?

2010-08-07 10:17:27
Hi Folks,

Why is this XPath 1.0 expression illegal:

   .[A]

whereas this XPath 1.0 expression is legal:

   self::node()[A]


Isn't '.' a shorthand for 'self::node()'?  Shouldn't I be able to interchange 
the two in any expression?

/Roger

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