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RE: [xsl] Selecting lots of nodes with lots of criteria

2010-09-06 02:41:42
Hi Ken.
Thanks for the explanations. I will have a look at your site to get the full 
picture.

Regards,
Fabien


-----Message d'origine-----
De : G. Ken Holman [mailto:gkholman(_at_)CraneSoftwrights(_dot_)com] 
Envoyé : jeudi 2 septembre 2010 18:35
À : xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Objet : RE: [xsl] Selecting lots of nodes with lots of criteria

At 2010-09-02 18:30 +0200, Fabien Tillier wrote:
Is this like an Index on a table ?

More like a lookup table of nodes.  The match= 
specifies the node in one column (say "left 
column"), and the use= specifies the lookup value 
in another column (say "right column").

One then uses key() to return all nodes from the 
left column whose corresponding lookup value is 
the right column is the second argument of the function call.

There are drawings on this page that may help:

   http://www.CraneSoftwrights.com/resources/xslkeys/index.htm

I hope this helps.

. . . . . . . . Ken

-----Message d'origine-----
De : Martin Honnen [mailto:Martin(_dot_)Honnen(_at_)gmx(_dot_)de]
Envoyé : jeudi 2 septembre 2010 17:38
À : xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Objet : Re: [xsl] Selecting lots of nodes with lots of criteria

Fabien Tillier wrote:

select="//Row[NUMERO = (1, 2, 3, 4, 5, 6, 7, 8)]"
is working !!!! (and a lot more faster...)

If speed matters you could of course define a key
   <xsl:key name="k1" match="Row" use="NUMERO"/>
and then use
   select="key('k1', (1, 2, 3, 4, 5, 6, 7, 8))"


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