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Re: [xsl] Preceding siblings test

2010-09-14 10:23:26
Hintz, David wrote:

I'm still a novice at XSLT and am having a problem coming up with a test for 
elements preceding a particular element, but only up to the first occurrence of 
the same (or parent) element.  For example, in this XML:

<list>
<a/>
<item>...</item>
<b/><b/><a/>
<item>...</item>
<item>...</item>
<a/><a/>
<item>...</item>
</list>

Assume in this example, <a> and <b> elements can occur before each item (any number of each).  
When I start processing an <item>, how do I get a list of just those nodes before the first preceding 
<item> or parent <list> element?

With XSLT 2.0 you can use the XPath 2.0 '>>' operator
  <xsl:template match="item">
<xsl:variable name="preceding-item" select="preceding-sibling::item[1]"/> <xsl:variable name="preceding-abs" select="preceding-sibling:a[. &gt;&gt; $preceding-item] | preceding-sibling:b[. &gt;&gt; $preceding-item]"/>
  </xsl:template>

It sounds however as if you might want to consider
  <xsl:for-each-group select="*" group-ending-with="item">
in a template matching the "list" element. That's also XSLT 2.0 however.




--

        Martin Honnen
        http://msmvps.com/blogs/martin_honnen/

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