Ah excellent!, thanks for showing me how count *could* have been used.
I will go tiwh the position() function as well.
Thanks!
-----Original Message-----
From: Michael Kay [mailto:mike(_at_)saxonica(_dot_)com]
Sent: Friday, September 17, 2010 5:12 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Hello - how do I use the count function properly?
And on every 4th subcategory I just want to set the margin-
right: 0px.
Here is the XSL and my attempt.
Please guide me.
<xsl:template match="category">
<xsl:for-each select="child::category">
<xsl:choose>
<xsl:when test="count(/child::category)=4 or
count(/child::category)=8">
There are several significant problems with this code.
First, xsl:for-each sets the context node, and any path expression
immediately within the for-each selects using that context node as its
start point. If you wrote "child::category" or "./child::category", you
would be testing whether the category node you are currently processing
has 4 (or 8) children called category, whereas you actually want to test
whether it has 3 (or 7) preceding siblings called category.
Secondly, by writing /child:category, you are not selecting children of
the context node, but children of the root (document) node at the top of
the tree. (A document node in a well-formed XML document has exactly one
element child, so testing whether it has 4 or 8 children will always
return false.)
You could write this as
<xsl:for-each select="child::category">
<xsl:choose>
<xsl:when test="count(preceding-sibling::category) = 3 or
count(preceding-sibling::category) = 7"
but I would tend to write it as
<xsl:for-each select="child::category">
<xsl:choose>
<xsl:when test="position() mod 4 = 0" ...
The position() function returns 1, 2, 3, ,,, in successive executions of
the xsl:for-each body.
Michael Kay
Saxonica
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