Works perfectly, thanks!
-- Jeff
On 09 21, 10, at 3:56 PM, Michael Kay wrote:
First parse the string and convert to a sequence of integers,
something like:
<xsl:for-each select="tokenize(., ',\s+')">
<xsl:choose>
<xsl:when test="contains(., '-')">
<xsl:sequence select="xs:integer(substring-before(., '-') to
xs:integer(substring-after(., '-')"/>
</
<xsl:otherwise>
<xsl:sequence select="xs:integer(.)"/>
</
</
</
Then do grouping using a method first suggested by David Carlisle on
this list:
<xsl:for-each-group select="..." group-adjacent=". - position()">
<xsl:choose>
<xsl:when test="count(current-group()) gt 1">
<xsl:value-of select="current-group()[1], current-group()[last()]"
separator="-"/>
</
<xsl:otherwise>
<xsl:value-of select="current-group()[1]"/>
</
</
</
On 21/09/2010 8:09 AM, Jeff Sese wrote:
Hi,
If i have a node like:
<node>1, 2, 3, 5-8, 9, 11, 15</node>
How can I make it as:
<node>1-3, 5-9, 11, 15</node>
I'm using XSLT 2.0
Thanks,
-- Jeff
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