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Re: [xsl] String manipulation XSLT 1.0

2010-09-24 06:41:43
What about:

<xsl:template match="given-name">
        <xsl:variable name="replaced">
                <xsl:call-template name="replace-substring">
                        <xsl:with-param name="original" select="."/>
                        <xsl:with-param name="substring" select="'.'"/>
                        <xsl:with-param name="replacement" select="'. '"/>
                        </xsl:call-template>
                </xsl:variable>
        <xsl:copy>
                <xsl:value-of select="normalize-space($replaced)"/>
                </xsl:copy>
        </xsl:template>

(no change to "replace-substring")

Input:
<given-name>A.H.</given-name>
<given-name>A. H.O.</given-name>
<given-name>X-Y.Z.B.</given-name>

output:
<given-name>A. H.</given-name>
<given-name>A. H. O.</given-name>
<given-name>X-Y. Z. B.</given-name>

Is this correct?

Regards,
EB


On Fri, Sep 24, 2010 at 12:56 PM,  
<pankaj(_dot_)c(_at_)thomsondigital(_dot_)com> wrote:
What do you mean "all spaces"? It only removes leading and trailing
spaces, and duplicate spaces, but it will leave a space between two
non-space characters if there was at least one...

If you read my original post or whole thread it says

I have an element,

Input
====
<given-name>A.H.</given-name>

Output
====
<given-name>A. H.</given-name> <!--  Notice the space after A.  -->

Martin has given a nice solution for it and almost fits the bill except I
do not need space after "." in last initial.

The best I have done is below. Only the issue with <xsl:template
name="replace-substring"> which adds space even after the last initial. So
if I use normalize-space() it removes the extra space added by template or
MIGHT POSSIBLE I AM NOT CORRECTLY USING IT.
Hope this makes myself clear.



<xsl:template match="given-name">
<xsl:copy>
   <xsl:choose>
   <xsl:when test="string-length(.)=2 and contains(.,'.')">
       <xsl:value-of select="."/>
   </xsl:when>
   <xsl:when test="string-length(.)=4 and contains(.,'.')">
       <xsl:value-of select="concat(substring-before(., '.'), '. ',
substring-after(., '.'))"/>    </xsl:when>
   <xsl:otherwise>

                   <xsl:call-template name="replace-substring">
                       <xsl:with-param name="original" select="."/>
                       <xsl:with-param name="substring" select="'.'"/>
                       <xsl:with-param name="replacement" select="'. '"/>
                   </xsl:call-template>
   </xsl:otherwise>
   </xsl:choose>
 </xsl:copy>
</xsl:template>

<xsl:template name="replace-substring">
<xsl:param name="original"/>
<xsl:param name="substring"/>
<xsl:param name="replacement" select="'. '"/>
<xsl:choose>
   <xsl:when test="contains($original, $substring)">
       <xsl:value-of select="substring-before($original, $substring)"/>
       <xsl:copy-of select="$replacement"/>
       <xsl:call-template name="replace-substring">
           <xsl:with-param name="original"
select="substring-after($original, $substring)"/>
           <xsl:with-param name="substring" select="$substring"/>
           <xsl:with-param name="replacement" select="$replacement"/>
       </xsl:call-template>
   </xsl:when>
   <xsl:otherwise>
       <xsl:value-of select="$original"/>
   </xsl:otherwise>
</xsl:choose>
</xsl:template>

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