[xsl] Returning a value from a template

I have been scratching my head on how to return a value from a called template 
which includes a for loop. A snippet of the XML fragment is as follows:

 <Loop-N1>
      <Segment-N1>
         <Element-98>BT</Element-98>
         <Element-93 xsi:nil="true"/>
         <Element-66>21</Element-66>
         <Element-67>RA0129937</Element-67>
      </Segment-N1>
   </Loop-N1>
   <Loop-N1>
      <Segment-N1>
         <Element-98>ST</Element-98>
         <Element-93>ABC COLUMBUS DIVISION</Element-93>
         <Element-66>11</Element-66>
         <Element-67>RA0314562</Element-67>
      </Segment-N1>
   </Loop-N1>

The element <Loop-N1> can occur multiple times. If one of the <Element-66>'s 
contain a value of "21" then I need to generate a fixed string value else I 
need 
to generate another fixed string literal. So I tried creating a named template 
and calling this from my main template like a function:

   <xsl:template name="getOrderSource">

    <xsl:for-each select="/ns0:Transaction-850/ns0:Loop-N1">
        <xsl:if test='ns0:Segment-N1/ns0:Element-66 = "21"'>
          <xsl:variable name="ordrSrc" select="NAEDI"/>
        </xsl:if>
    </xsl:for-each>

    <xsl:choose>
      <xsl:when test='$orderSrc = "NAEDI"'>
        <xsl:text disable-output-escaping="no">NAEDI</xsl:text>
      </xsl:when>
      <xsl:otherwise>
        <xsl:text disable-output-escaping="no">NAEDIBrokerage</xsl:text>
      </xsl:otherwise>
    </xsl:choose>
  </xsl:template>

This was called like:
  <corecom:ID>
            <xsl:call-template name="getOrderSource"/>
  </corecom:ID>


However, I realized that the variable declared inside the for-each is not 
visible to the xsl:choose that follows. What I was trying to do is to set a 
flag 
to indicate that the element exists and then return the appropriate string 
literal. Would there be a simpler way to do this? Thanks! 



      

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