>
> I want to find out if the two nodesets share one or more elements. I
> only want a comparison regarding their nodenames not the values of
> the nodes. In the above example $me1 and $me2 share the name of one
> element: and that is the element "<a/>". So my nodeset comparison
> should return "true".
In XSLT 1.0:
<xsl:value-of select="name($me1) = name($me2)"/>
Unfortunately, no. In XSLT 1.0, name($nodeset) returns the name of the
first item in the nodeset.
I don't see any alternative to coding it as a nested loop
<xsl:variable name="matches">
<xsl:for-each select="$me1">
<xsl:for-each select="$me2">
<xsl:if test="name($me1) = name($me2)">yes</xsl:if>
</
</
</
<xsl:if test="contains($matches, 'yes')"
Michael Kay
Saxonica
In 2.0:
<xsl:value-of select="$me1/name() = $me2/name()"/>
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