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Re: [xsl] Finding the position of an element wrt to other element

2010-11-19 04:56:56
Sorry, but I don't understand the problem. I fail to see where "342"
(or 3, 4, 2?) should come from.

When you say "relative position", then there's always two elements
involved, and you'll have to specify for both how they can be
identified.

Also, what unit are you thinking of when you mean "relative position"?
Number of elements between the first and last <a>
here
   <a p="1"/><b/><a/><a/><b/><a/>
could be 4 (including b) or 2 (<a> only).

Are you using XSLT 2.0? If not, I won't be able to help you at all.
-W


On 19 November 2010 11:16, Rashi Bhardwaj 
<rashi(_dot_)bhardwaj(_at_)gmail(_dot_)com> wrote:
Hi,

I want the position of an element (there is a condition for selecting
that element) relative to other element

Input XML:
<test>
<a>
<b name ='1'></b>
<b name ='2'></b>
<b name ='3'>
<c></c>
</b>
<b name ='4'>
       <c></c>
       <c></c>
</b>
<b name ='4'>
       <c></c>
       <c></c>
</b>
</a>
<a>
<b name ='1'></b>
<b name ='2'>
<c></c>
</b>
<b name ='3'></b>
<b name ='4'>
       <c></c>
</b>
</a>
</test>

XSL I using:

<xsl:template match="/">
               <html>
                       <body>
                       <table>
                               <tbody>
                                       <tr>
                                               <th>
                                               <xsl:value-of 
select="$CustomSelect"/>
                                               </th>
                                       </tr>
                               </tbody>
                       </table>
                       </body>
               </html>
       </xsl:template>
       <xsl:variable name="CustomSelect">
                       <xsl:text>position: </xsl:text>
                               <xsl:call-template name="test">
                               </xsl:call-template>
               </xsl:variable>
               <xsl:template name="test">
 <xsl:call-template name="test2">
 <xsl:with-param name="node" select="//b[c][not(@name
=preceding::b[child::c]/@name)]/@name"/>
   </xsl:call-template>
    </xsl:template>
<xsl:template name="test2">
<xsl:param name="node"/>
<xsl:for-each select="$node">
<xsl:value-of select="position()"/>
<xsl:if test="position()!=last()"/>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>

Output I m getting is position 123, but i want it should count all b
from top to end at any level and give relative position like here it
should give 342. I m getting how to go ahead...please help  me out
thanks......





Rashi Bhardwaj

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