Fabien Tillier wrote:
What could be the XPath expression to get the maximum number of nodes of
level=50 in data those keycode starts like the level=40 line ?
Here the answer would be 3 as the maximum number of level = 50 nodes for
a given level = 40 is 3
As you originally asked for an XPath expression here is a more compact
form of the previous suggestion:
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="2.0">
<xsl:param name="l1" select="'50'"/>
<xsl:param name="l2" select="'40'"/>
<xsl:key name="k1" match="row" use="level"/>
<xsl:template match="/">
<xsl:value-of
select="max(
for $group in key('k1', $l2)
return count(key('k1', $l1)[starts-with(keycode,
$group/keycode)])
)"/>
</xsl:template>
</xsl:stylesheet>
--
Martin Honnen
http://msmvps.com/blogs/martin_honnen/
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