On 29/12/2010 15:21, Mark wrote:
Happy new year! Thanks for all the help this list has given me over the
past two years. My question:
I have an XML document that looks like the listing below. I want to sort
the <List> by <Item> so that all the <Items> with one <Data> element are
followed by all the <Items> with two <Data> elements, and so on, until
the last <Items> in the output list have the most <Data> elements. The
<Data> elements have to remain inside their original parent <Item>.
No clue how to begin. Can you point me in the right direction?
Thanks,
Mark
<List>
<Item>
<Data>...</Data>
... <!—possibly 1 to 10 or so <Data> elements in each parent <Item>
element.
<Data>...</Data>
</Item>
... <!—400 <Item> elements in the <List> –>
</List>
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--
________________________________________________________________________
This e-mail has been scanned for all viruses by Star.
________________________________________________________________________
xsl;for-each select=Item
xsl:sort select="count(Data)"
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--