Re: [xsl] Get the element to original position XSLT 1.0

    <xsl:template match="comment()">
                 <xsl:variable name="commentFootnoteId"
select="substring-before(substring-after(., '&quot;'), '&quot;')" />
                 <xsl:copy-of select="/chapter/footnote[@id = 
$commentFootnoteId]" />
   </xsl:template>


Perfect. I started using keys but this one seems to be more clean.

Thanks Mukul.

Best,
Pankaj

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