Re: [xsl] how find out end position using 'for' loop

Try replacing: ']+'
with: if ($i != $end) then ']+' else ']'

-Brandon :)


On Tue, Jun 14, 2011 at 12:47 AM, JS Rawat <jrawat(_at_)aptaracorp(_dot_)com> 
wrote:
> Hi Everybody,
> Have anyone any idea about the below problem. I want + sign between two 
> RefArray (RefArray[11] + RefArray[12]) but not in the last (RefArray[12]+ 
> RefArray[13]+ should be RefArray[12]+ RefArray[13]).
>
> Input
> <link class="bibcit" rid="FileName_bib11">11&#x2013;13</link>
>
> XSLT
>
> <xsl:template match="link">
>  <xsl:choose>
>  <xsl:when test="@class='bibcit'">
>     <xsl:variable name="bibtext" select="."/>
>     <xsl:choose>
>      <xsl:when test="contains($bibtext, '&#x2013;') and 
> substring-before($bibtext,'&#x2013;') castable as xs:integer">
>        <xsl:variable name="start" 
> select="xs:integer(substring-before($bibtext,'&#x2013;'))"/>
>        <xsl:variable name="end" 
> select="xs:integer(substring-after($bibtext,'&#x2013;'))"/>
>        <a class="bibcit" href="references.htm#{substring-after(@rid,'_')}" 
> onmouseout="startTimeout()">
>         <xsl:attribute name="onmouseover">refpopup('REF',<xsl:value-of 
> select="for $i in $start to $end return 
> concat('RefArray[',$i,']+')"/>)</xsl:attribute><xsl:apply-templates/></a>
>      </xsl:when>
>     </xsl:choose>
>   </xsl:when>
>  </xsl:choose>
> </xsl:template>
>
> OUTPUT
> <a class="bibcit" href="references.htm#bib11" onmouseout="startTimeout()" 
> onmouseover="refpopup('REF',RefArray[11]+ RefArray[12]+ 
> RefArray[13]+)">11–13</a>
>
>
> Desired OUTPUT
> <a class="bibcit" href="references.htm#bib11" onmouseout="startTimeout()" 
> onmouseover="refpopup('REF',RefArray[11]+ RefArray[12]+ 
> RefArray[13])">11–13</a>
>
> Thanks in advance.
>
> ...JSR
>
>
>
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