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Re: [xsl] sequence as function parameter

2011-07-04 10:06:59
At 2011-07-04 16:46 +0200, Fabien Tillier wrote:
I am trying to create a simple function to multiply each item in a
sequence by each other (like a sum()).
My problem is that I am unable to have the parameter treated as a node
sequence (using saxon, so XSL2.0)

I have
<xsl:template name=" multiplie">

That is a template, not a function, so I'm guessing we aren't looking at the code that produced your result. Perhaps you are simply calling the template from the function?

        <xsl:param name="serie"/>
        <xsl:param name="result" as="xs:double"/>

Doesn't this have an initial value of 1? Your template won't work if you pass an initial sequence of only a single value because you are multiplying that by the result and the result has no value.

        <!--some test output -->
        <xsl:value-of select="$serie"/>-<xsl:value-of
select="$result"/>--
        ###<xsl:value-of select="count($serie)"/>###
        <!-- -->
        <xsl:choose>
                <xsl:when test="count($serie) gt 1">
                        <!-- make the multiplication between result and
the first item in the serie, then remove it and call again -->
                        <xsl:variable name="comp">
                                <xsl:value-of select="number($serie[1])
* $result"/>
                        </xsl:variable>

This is wastefully creating a node tree...

                        <xsl:call-template name=" multiplie">
                        <xsl:with-param name="serie"><xsl:copy-of
select="subsequence($serie,2)"/></xsl:with-param>

... as is this ...

                        <xsl:with-param name="result"><xsl:value-of
select="$comp"/></xsl:with-param>

... and that.

                        </xsl:call-template>
                </xsl:when>
                <xsl:otherwise>
                        <xsl:value-of select="number($serie[1]) *
$result"/>

Here is where your template won't work if you pass it an initial sequence of a single value.

...
So, the part where I do a count gets me 1, when I should have 4...
I have tried with
<xsl:param name="serie" as="node()*"/> but I have an error message
XTTE0790: Required item type of first argument of multiplie() is node();
supplied
  value has item type xs:double

If you want to pass either nodes or atomic values then use:

  as="item()*"

I am a bit out of ideas....

I think you are looking too deep. And certainly your use of XSLT constructs could be more streamlined. I believe you can implement your requirement completely in a one-line template with one parameter.

Does the example below help?

. . . . . . . . Ken

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
  xmlns:f="urn:X-Fabien"
  version="2.0">

<xsl:template match="/">
?<xsl:variable name="seq" select="(6.8E-06,5.5E-06,7.1E-06,7.3E-06)"/>
Fabien's test: <xsl:value-of select="f:multiplie($seq)"/>
Ken's tests: <xsl:value-of select="f:multiplie((7))"/>
and: <xsl:value-of select="f:multiplie((1,2,3,4,5))"/>
</xsl:template>

<xsl:function name="f:multiplie">
  <xsl:param name="seq" as="item()+"/><!--at least one item in sequence-->
  <xsl:sequence select="if( count($seq)=1 ) then $seq
                        else $seq[1] * f:multiplie($seq[position()>1])"/>
</xsl:function>
</xsl:stylesheet>

--
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