Hi Martin.
This one is easier for me to use :)
Seems to be doing the expected work
<para><phrase role="rtf">
norepinephrine
transporter<subscript/>
<emphasis>(h) </emphasis>
(antagonist radioligand)
</phrase></para>
Thank you for giving me the complete answer :)
Regards,
Fabien
-----Message d'origine-----
De : Martin Honnen [mailto:Martin(_dot_)Honnen(_at_)gmx(_dot_)de]
Envoyé : mercredi 3 août 2011 17:12
À : xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Objet : Re: [xsl] Removing nodes with text content ?
Fabien Tillier wrote:
Hi Andrew.
Hum... should I say I can't have it work ?
<xsl:for-each-group select="para/phrase" group-adjacent="@role">
<xsl:copy-of select="."/>
</xsl:for-each-group>
Gives
<?xml version="1.0" encoding="UTF-8"?>
<phrase role="rtf">
norepinephrine
</phrase>
Try along these lines
<xsl:template match="para">
<xsl:copy>
<xsl:for-each-group select="*"
group-adjacent="boolean(self::phrase[@role = 'rtf'])">
<xsl:choose>
<xsl:when test="current-grouping-key()">
<phrase role="rtf">
<xsl:apply-templates select="current-group()/node()"/>
</phrase>
</xsl:when>
<xsl:otherwise>
<xsl:apply-templates select="current-group()"/>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each-group>
</xsl:copy>
</xsl:template>
Might need an identity transformation template for all nodes you want to
copy by the apply-templates in the otherwise branch.
--
Martin Honnen --- MVP Data Platform Development
http://msmvps.com/blogs/martin_honnen/
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