fn:max() applied to //item[@id=$idref]/@date gives you the maximum
date of the sequence with that specific id, and you know how to use
that in the <xslvalue-of ...>.
This implies that date values are unique.
-W
On 5 September 2011 11:36, Emma Burrows
<Emma(_dot_)Burrows(_at_)rpharms(_dot_)com> wrote:
Hopefully a quick question. Using XSLT 2.0, I am filtering entries in an
input file based on their ids. The only problem is that I've been given an
update to the original input file which includes many duplicates, some of
which are identical and some of which have been updated. For any given id, I
need to look up the item with the most recent date.
So say I have the following input file:
<items>
<item id='1' date='2011'>Item1</item>
<item id='2' date='2009'>Item2</item>
<item id='3' date='2002'>Item3</item>
<item id='2' date='2011'>Item2</item>
<item id='3' date='2002'>Item3</item>
</items>
For example, the Xpath in question looks like this right now (long-winded but
more efficient path-finding syntax simplified to // for this example, and
$idref obviously contains a valid id):
<xsl:value-of select="normalize-space(//item[@id=$idref])"/>
What is the best way to filter that to return only the item whose @date is
the highest for all items with @id=$idref?
Thanks!
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